Asked by FrostyFairy
Find the solution to the system
y = 2x2 - 2x - 3
y = -2x + 2
A) (-1,1) and (1, -3)
B) (0, -1) and (-0.5, 0)
C) (0.5, -3.5) and (0, -3)
D) (2, 1) and (0,0)
I saw the question asked with NoU, and I had gotten the same result as the teacher, however I do not know which one it is(a,b,c, or d)
y = 2x2 - 2x - 3
y = -2x + 2
A) (-1,1) and (1, -3)
B) (0, -1) and (-0.5, 0)
C) (0.5, -3.5) and (0, -3)
D) (2, 1) and (0,0)
I saw the question asked with NoU, and I had gotten the same result as the teacher, however I do not know which one it is(a,b,c, or d)
Answers
Answered by
Damon
-2 x + 2 = 2 x^2 - 2 x - 3
2 x^2 - 5 = 0
x^2 = 2.5
x = +/- sqrt 2.5
please check for typos
2 x^2 - 5 = 0
x^2 = 2.5
x = +/- sqrt 2.5
please check for typos
Answered by
FrostyFairy
yeah taht is the same thing, but I don't know what answer that is. I had gotten +/- sqrt 5/2.
Answered by
oobleck
so there must be a typo in the question.
Answered by
FrostyFairy
It shows it as
y =2x^2 -2x-3
y =-2x+2
y =2x^2 -2x-3
y =-2x+2
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