Asked by quarantine
Suppose that
f(x)=log(base 7) (2x^2+1).
Find f′(2).
f(x)=log(base 7) (2x^2+1).
Find f′(2).
Answers
Answered by
oobleck
Since logx<sub><sub>7</sub></sub>x = lnx/ln7,
f'(x) = 1/ln7 * 4x/(2x^2+1)
now evaluate at x=2
f'(x) = 1/ln7 * 4x/(2x^2+1)
now evaluate at x=2
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