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Use implicit differentiation to find an equation of the tangent line to the curve. sin(x+y)=4x−4y at the point (π,π). Tangent Line Equation:

Suppose f is a one-to-one, differentiable function and its inverse function f^−1 is also differentiable. One can show, using implicit differentiation (do it!), that (f^−1)′(x)=1 / f′(f^−1(x)) Find (f^−1)′(−6) if f(−1)=−6 and f′(−1)=3/5. (f^−1)′(−6)=

Given that f(x)=2x+cos(x) is one-to-one, use the formula (f^−1)′(x)=1 / f′(f^−1(x)) to find (f^−1)′(1). (f^−1)′(1)=

Suppose that f(x)=log(base 7) (2x^2+1). Find f′(2).

f(x)=7^(x^2+4x) Find f′(1)=

Let f(x)=8(sin(x))^x. Find f′(3). f′(3)=