Asked by Lindsey
What method(s) would you choose to solve the equation? Explain your reasoning.
4x^2-48=0
a. Quadratic formula, graphing; the equation cannot be factored easily since the numbers are large.
Selected:b. Square roots; there is no x-term.
c. Factoring; the equation is easily factored.
d. Quadratic formula, completing the square or graphing; the coefficient of x2-term is 1, but the equation cannot be factored.
4x^2-48=0
a. Quadratic formula, graphing; the equation cannot be factored easily since the numbers are large.
Selected:b. Square roots; there is no x-term.
c. Factoring; the equation is easily factored.
d. Quadratic formula, completing the square or graphing; the coefficient of x2-term is 1, but the equation cannot be factored.
Answers
Answered by
Reiny
4x^2-48=0
No x term, this is the easiest type, first divide each term by 4 to get
x^2 - 12 = 0
add 12 to both sides
x^2 = 12
take √ of both sides
x = ± √12 = ± 2√3
No x term, this is the easiest type, first divide each term by 4 to get
x^2 - 12 = 0
add 12 to both sides
x^2 = 12
take √ of both sides
x = ± √12 = ± 2√3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.