Asked by lucy
A village water tank is in the form of a frustrum of a cone of height 3.2 cm.The top and bottom radii are 18cm and 24cm respectively.Calculate:The surface area of the tank
Answers
Answered by
oobleck
A town water tank with dimensions in cm? I don't think so! But, using the numbers given,
since 18/24 = 3/4, the top 3/4 of the cone is missing.
So, the whole cone would have a height of 12.8, with a slant height of 27.2
The surface of the whole cone is πr(r+s) = 1228.8π
The area of the missing 3/4 is 9/16 the whole area, or 690.75π
Thus, the area of the frustrum is 538.05π + 324π = 862.05π
since 18/24 = 3/4, the top 3/4 of the cone is missing.
So, the whole cone would have a height of 12.8, with a slant height of 27.2
The surface of the whole cone is πr(r+s) = 1228.8π
The area of the missing 3/4 is 9/16 the whole area, or 690.75π
Thus, the area of the frustrum is 538.05π + 324π = 862.05π
Answered by
lucy
how did you get 12.8
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