in these odd units
momentum before = 19(39) + 36 (19) = 741+684 = 1425
momentum after = 19 Va + 36 Vb = 1425
Ke before = .5 * 19*39^2 + .5*36*19^2 = Ke after = .5*19 Va^2 + .5*36 Vb^2
A(n) 19 g object moving to the right at
39 cm/s overtakes and collides elastically with
a 36 g object moving in the same direction at
19 cm/s.
Find the velocity of the slower object after
the collision.
Answer in units of cm/s.
1 answer
1 answer