Asked by lucy
When 34.8grams of potassium sulphate was dissolved in 500cm cubed distilled water.calculate :the concentration of potassium sulphate in grams/litre.the molarity of the solution
Answers
Answered by
oobleck
you have the numbers and the units, so do the math.
1L = 1000cm^3, so 500cm^3 = 0.5L
34.8g / 0.5L = _____ g/L
1L = 1000cm^3, so 500cm^3 = 0.5L
34.8g / 0.5L = _____ g/L
Answered by
DrBob222
For molarity, M = mols/L. Convert 34.8 g K2SO4 to mols.
mols = g/molar mass = ?
mols = g/molar mass = ?
Answered by
Shanty
Concentration in g/l
500/1000= 0.5 l
Therefore 34.8g/0.5 l= 69.6g/l
b)Molarity= no.of moles/volume in litre
No of moles= mass/molar mass of K2SO4
34.8/174= 0.198
M= 0.198/0.5= 0.396
500/1000= 0.5 l
Therefore 34.8g/0.5 l= 69.6g/l
b)Molarity= no.of moles/volume in litre
No of moles= mass/molar mass of K2SO4
34.8/174= 0.198
M= 0.198/0.5= 0.396
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