A committee consists of six men and four women .A subcommittee is made by randomly choosing three of the committee members. What is the probability that (a) they are all women (b) two of them are men?

Answer 1

(a) 4/10 * 3/9 * 2/8
(b) 4/10 * 6/10 * 6/10 is the chance that only the 1st one chosen is a woman. Now, what about other options?