Question

Table: Time (weeks) 0 2 6 10
Level 210 200 190 180

The table above gives the level of a person’s cholesterol at different times during a 10-week treatment period. What is the average level over this 10-week period obtained by using a trapezoidal approximation with the subintervals [0, 2], [2, 6], and [6, 10] ?

Answer 1

the area would, of course, be the sum of the areas of the trapezoids, which you surely know how to calculate:

A = (210+200)/2 * 2 + (200+190)/2 * 4 + (190+180)/2 * 4

and the average value is A/10