Asked by Gameknight
1.Solve the system of equations.
y = 2x^2 - 3
y = 3x - 1
a. no solution
b. (-1/2, 5), (2, -5/2)
c. (-1/2, -5/2), (2,5)
d. (1/2, 5/2), (2, 5)
2.how many real number solutions does the equation have 0 = -3x^2 + x - 4
a. 0
b. 1
c. 2
d. 3
3. solve the equation by completing the square. If necessary round to the nearest hundredth.
x^2 - 18x = 19
a. 1; 19
b. -1; 19
c. 3; 6
d. -3; 1
4. solve. x^2 - 81 = 0
a. 0
b. -9
c. -9, 9
d. 9
5. which model is most appropriate for the data shown in the graph below? (need wedsite to know the problem)
a. quadratic
b. linear
c. exponential
d. line
for questions 6-9, match the equation to its corresponding graph.
(need wedsite to know the problem)
a, b, c, d
6. y=-2x^2+2
7. y=-x^2
8. y=2x^2
9. y=3x^2-4
Graph the quadratic functions y = -2x^2 and y = -2x^2 + 4 on a separate piece of paper. Using those graphs, compare and contrast the shape and position of the graphs.
(text box under question)
Answers
Answered by
Gameknight
i know this is cheating but i need the answers please
Answered by
Writeacher
Absolutely not!
But if YOU post what YOU THINK, someone might help you.
But if YOU post what YOU THINK, someone might help you.
Answered by
Reiny
I will not give you the answers, but tell you what you have to do
1. y = 2x^2 - 3
y = 3x - 1
both right sides are equal to y, so they must be equal to each other
2x^2 - 3 = 3x - 1
2x^2 - 3x - 2 = 0
this factors nicely
2.
0 = -3x^2 + x - 4
3x^2 - x + 4 = 0 , a=3, b= -1, c = 4
b^2 - 4ac = 1 - 4(3)(4) = -47
you would be dealing with √-47 which is not a real number, so what do you think?
3. x^2 - 18x = 19
take half of the -18, square that, and add it to both the left and the right side.
x^2 - 18x + 81 = 19 + 81
(x-9)^2 = 100
carry on
4. x^2 - 81 = 0
difference of squares ...
(x+9)(x-9) = 0
and the solutions are .....
5. ...... ?
1. y = 2x^2 - 3
y = 3x - 1
both right sides are equal to y, so they must be equal to each other
2x^2 - 3 = 3x - 1
2x^2 - 3x - 2 = 0
this factors nicely
2.
0 = -3x^2 + x - 4
3x^2 - x + 4 = 0 , a=3, b= -1, c = 4
b^2 - 4ac = 1 - 4(3)(4) = -47
you would be dealing with √-47 which is not a real number, so what do you think?
3. x^2 - 18x = 19
take half of the -18, square that, and add it to both the left and the right side.
x^2 - 18x + 81 = 19 + 81
(x-9)^2 = 100
carry on
4. x^2 - 81 = 0
difference of squares ...
(x+9)(x-9) = 0
and the solutions are .....
5. ...... ?
Answered by
Ro
Here are the correct answers;
1. C (-1/2, -5/2), (2,5)
2. A 0
3. B -1;19
4. C -9,9
5. C Exponential
MATCHING
6. A
7. D
8. C
9. B
10. ESSAY
1. C (-1/2, -5/2), (2,5)
2. A 0
3. B -1;19
4. C -9,9
5. C Exponential
MATCHING
6. A
7. D
8. C
9. B
10. ESSAY
Answered by
ss
y=3x+2
4x+2y=24
helppp
4x+2y=24
helppp
Answered by
Whatever
For the essay question
10.Graph the quadratic functions y=-2x^2 and y=-2x^2+4 on a separate piece of paper. Using those graphs, compare and contrast the shape and position of the graphs.
Answer: The first function has a vortex at (0,0), while the second function has a vortex of (0,4). The difference between the two is that the second one is higher up on the y-axis than the first one, that it intercepts at a higher point than the first. They are the same without that difference. They both have the same shape too.
10.Graph the quadratic functions y=-2x^2 and y=-2x^2+4 on a separate piece of paper. Using those graphs, compare and contrast the shape and position of the graphs.
Answer: The first function has a vortex at (0,0), while the second function has a vortex of (0,4). The difference between the two is that the second one is higher up on the y-axis than the first one, that it intercepts at a higher point than the first. They are the same without that difference. They both have the same shape too.
Answered by
Carson
RO is 100% right. thanks RO :)
Answered by
Can’t put real name😪
L Writeacher
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