Asked by Dee

Two cars have the same mass, but one is moving three times faster than the other. How much more work will be needed to stop the faster car?

Answers

Answered by Damon
KE = (1/2) m v^2
You must do enough work (Force times braking distance) to equal the original Kinetic energy.
W1 = (1/2) m v^2
W2 = (1/2) m (3v)^2 = (1/2) m v^2 * 9
so
nine times as much
Answered by Yan
I guess NINE TIMES AS MUCH
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions