Question

(a) Construct a quadrilateral ABCD in which AB = 10cm , angle ABC = 120° , angle BAD = 60°, BC =7cm and AD = 11cm.
(b) Measure and write the length of CD.
(c) Within the quadrilateral ABCD draw the locus of points which are
(i) 8cm from A,
(ii) equidistant from BC and CD
(d) A point p , within the quadrilateral ABCD , is such that it is 8cm from A and equidistant from BC and CD .Label point p.
(e) Another point Q within the quadrilateral ABCD , is such that it is nearer to CD than to BC and greater than or equal to 8cm from A . indicate , by shading , the region in which Q must lie.

Answer 1

Ok, I made a sketch of your figure, we could not possible help you with your own.
I just followed the steps in sequence, was pretty straight-forward

b) can't help you with that, can't see your quad, but I could calculate it
(using the cosine law you can find CA, then by the sine law you can find angle CAB
after than find angle CAD, then by another cosine law you can find CD) , Did you get appr 8.7 ?

c) i) wouldn't that just be a circle with radius of 8 ?
ii) how about the bisector of angle BCD ?

d) mmmhhhh, how do you think that ties in with c) ?

e) go for it, you got your diagram.

Answer 2

That explanation doesn't help.

Answer 3

Show it then