Asked by Popoola tunmise
construct a quadrilateral PQRS such that /PQ/=6cm,/QS/=/RS/=9,PQS=75° find /PS/and /QR/.
Answers
Answered by
oobleck
use the law of cosines to find PS:
PS^2 = 6^2 + 9^2 - 2*6*9*cos75°
PS ≈ 9.44
As for QR, that's a bit harder. There is no way to say just where point R is. All you know is that it lies on a circle with center at S, with radius 9.
Try drawing PQRS and you will see that you need a bit more information.
PS^2 = 6^2 + 9^2 - 2*6*9*cos75°
PS ≈ 9.44
As for QR, that's a bit harder. There is no way to say just where point R is. All you know is that it lies on a circle with center at S, with radius 9.
Try drawing PQRS and you will see that you need a bit more information.
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