Asked by tryingtosecurethebag
The question:
If α =.05, 2-tail, would you consider responses of 9 or more words to be a rare occurrence? Why or why not? How about a score of 10?
My work:
Drew a distribution with .025 and .025 at both ends and .95 in between.
Then:
z9=9-6/2=3/2=1.5 (Located under z-score table as .4332)
z10=10-6/2=4/2=2.0 (Located under z-score table as .4772).
Then:
.4772+.4332=.9104=.91
Then: .95-.91=.04
Did I use the correct mathematical approach?
If α =.05, 2-tail, would you consider responses of 9 or more words to be a rare occurrence? Why or why not? How about a score of 10?
My work:
Drew a distribution with .025 and .025 at both ends and .95 in between.
Then:
z9=9-6/2=3/2=1.5 (Located under z-score table as .4332)
z10=10-6/2=4/2=2.0 (Located under z-score table as .4772).
Then:
.4772+.4332=.9104=.91
Then: .95-.91=.04
Did I use the correct mathematical approach?
Answers
Answered by
tryingtosecurethebag
I forgot to include this information but the mean in the problem was stated as 6 and the standard deviation was stated as 2.
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