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tryingtosecurethebag
Questions (11)
What is the meaning behind critical values? Like if I have a confidence interval of 95 (in which the z-score in 1.96) and I have
1 answer
415 views
The question is asking how to calculate the confidence interval for p. The sample size/n is given and the mean of that sample
1 answer
361 views
Question: Between test 1 (score of 230 and mean of 210 and standard deviation of 22) and test 2 (score of 80 and mean of 70 and
3 answers
610 views
Question: If a distribution has a mean of 100 and a standard deviation of 15, what value would be +2 standard deviations from
2 answers
2,166 views
Can someone break down what each symbol of these formulas mean?
σ y-bar = σy/squareroot N σ(with ^) p subscript = square root
0 answers
311 views
Question: Find the weighted average.
value f 8 8 7 12 6 10 5 4 4 3 3 0 2 0 1 1 My work: ybar= (8x8)+ (7x12) + (6x10) + (5x4)+
2 answers
421 views
How do you find the area that is beyond a z-score?
1 answer
546 views
The question:
If α =.05, 2-tail, would you consider responses of 9 or more words to be a rare occurrence? Why or why not? How
0 answers
475 views
Question: For a normal distribution, use the given z-scores to find the requested probability:
Probability is greater than or
2 answers
482 views
The question:
If α =.05, 2-tail, would you consider responses of 9 or more words to be a rare occurrence? Why or why not? How
1 answer
459 views
Hello, I am trying to make sure that I'm doing this right.
Question: Determine the probability that a randomly drawn respondent
4 answers
505 views
Answers (6)
I think the formula is square root (p)- (1-p)/ n right? But to find p do I use 1-alpha/2? Is 0.10 for confidence interval 90? Like is it 1-0.10/2=.05?
Nevermind it is test 2. Test 1= z220=220-200/21=20/21=0.95=.33 Test 2= z90=90-80/8=10/8=1.25=.40
So I got 240 and divided that by the number of values and got 30 but that is nowhere near the right answer. I also know that since the average is weighted it is not 8+12+10+4+3+0+0+1/8.
I forgot to include this information but the mean in the problem was stated as 6 and the standard deviation was stated as 2.
@Reiny thank you!
That is what my ta taught me. I am trying to make sense of my notes because it is confusing me.