Asked by tryingtosecurethebag
                Hello, I am trying to make sure that I'm doing this right.
Question: Determine the probability that a randomly drawn respondent has x correctly identified words where x: is greater than or equal to 8.
Given : Mean of 6 and standard deviation of 2.
My work:
I first drew a picture of a normal distribution (straight line at 8 and the mean of 6 at the center. I shaded the line at 8 all the way to the right)I then used the x-mean/standard deviation formula.
8-6/2=1
The z-score is 1.0. So then I looked it up on my normal curve distribution table and found a value of .34. Then added .5 to .34 and got .84. Then 1-.84 and got .16 (.16 standard deviations above the mean). Looked that up on the table for a value of .0636. .0636 is my final answer.
            
        Question: Determine the probability that a randomly drawn respondent has x correctly identified words where x: is greater than or equal to 8.
Given : Mean of 6 and standard deviation of 2.
My work:
I first drew a picture of a normal distribution (straight line at 8 and the mean of 6 at the center. I shaded the line at 8 all the way to the right)I then used the x-mean/standard deviation formula.
8-6/2=1
The z-score is 1.0. So then I looked it up on my normal curve distribution table and found a value of .34. Then added .5 to .34 and got .84. Then 1-.84 and got .16 (.16 standard deviations above the mean). Looked that up on the table for a value of .0636. .0636 is my final answer.
Answers
                    Answered by
            R_scott
            
    not sure why you "looked up in the table" twice
the .16 that you got from the 1st iteration is the answer
you might want to go over your technique
    
the .16 that you got from the 1st iteration is the answer
you might want to go over your technique
                    Answered by
            tryingtosecurethebag
            
    That is what my ta taught me. I am trying to make sense of my notes because it is confusing me.
    
                    Answered by
            Reiny
            
    This is the best applet that I have found online.
http://davidmlane.com/normal.html
You can enter the mean and sd directly without bothering about z-scores
enter 6 as the mean
enter 2 as the sd
click on above and enter 8, you will get .84129.... directly
If your course requires you to show the z-score calculations etc,
you can still use this app to check your answers.
btw, you can also use the app to reverse the process by clicking on
"Value from an area" and going from there
    
http://davidmlane.com/normal.html
You can enter the mean and sd directly without bothering about z-scores
enter 6 as the mean
enter 2 as the sd
click on above and enter 8, you will get .84129.... directly
If your course requires you to show the z-score calculations etc,
you can still use this app to check your answers.
btw, you can also use the app to reverse the process by clicking on
"Value from an area" and going from there
                    Answered by
            tryingtosecurethebag
            
    @Reiny thank you!
    
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