Asked by Anonymous
what is the OH concentration of a solution with a pH of 12.4
Answers
Answered by
anonymous
pH + pOH = 14
12.4 + pOH = 14
pOH = 1.6
pOH = -log[OH-]
1.6 = -log[OH-]
10-1.6 = [OH-] = 0.0251 M
12.4 + pOH = 14
pOH = 1.6
pOH = -log[OH-]
1.6 = -log[OH-]
10-1.6 = [OH-] = 0.0251 M
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