Asked by Veronica
A sample of hydrogen exerts a pressure of 0.418 atm at 57.0° C. The gas is heated to 88.0° C at constant volume. What will its new pressure be?
Please show work
Please show work
Answers
Answered by
Damon
T1 = 273+ 57
T2 = 273 + 88
P1 = .418
V2 = V1
n and R constant so
n R/V = P/T = P1/T1 = P2/T2
P2 = .418 *(273+88)/(273+57)
T2 = 273 + 88
P1 = .418
V2 = V1
n and R constant so
n R/V = P/T = P1/T1 = P2/T2
P2 = .418 *(273+88)/(273+57)
Answered by
DrBob222
(P1/T1) = (P2/T2)
You don't have the PVT formula memorized? You need to remember only 1.
Just remember P1V1/T1. Of course that's the same at new conditions of P2V2/T2. LOOK at P1V1/T1. If T is constant use your finger to cover up T and you're left with P1V1 = P2V2. If P is constant, use your finger to cover P and you're left with V1/T1 = V2/T2. If V is constant, cover the V and P1V1/T1 becomes P1/T1 = P2/T2. That makes it easy to remember.
You don't have the PVT formula memorized? You need to remember only 1.
Just remember P1V1/T1. Of course that's the same at new conditions of P2V2/T2. LOOK at P1V1/T1. If T is constant use your finger to cover up T and you're left with P1V1 = P2V2. If P is constant, use your finger to cover P and you're left with V1/T1 = V2/T2. If V is constant, cover the V and P1V1/T1 becomes P1/T1 = P2/T2. That makes it easy to remember.
Answered by
Veronica
so its 0.46
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