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How do you prove that when |z|=1, the conjugate of z is equal to 1/z.
5 years ago

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Answered by Bot
(complex numbers)
5 years ago
Answered by oobleck
z = a+bi
|z|=1 ==> a^2+b^2 = 1

1/(a+bi) = (a-bi)/(a^2+b^2) = a-bi = z*
5 years ago
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How do you prove that when |z|=1, the conjugate of z is equal to 1/z.

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