Asked by kayli
The decomposition of SO2Cl2 is first order and has a rate constant of + 2.90 x 10^–4 s^–1. What is the concentration of SO2Cl2 after 840 seconds given that the initial concentration of SO2Cl2 is 0.0325M?
Answers
Answered by
DrBob222
ln(No/N) = kt
No = 0.0325
N = ?
k = 2.90E-4
t = 840
Substitute and solve for N. Post your work if you get stuck.
No = 0.0325
N = ?
k = 2.90E-4
t = 840
Substitute and solve for N. Post your work if you get stuck.