Question

What mass of lead (ii)trioxonitrate(v)pb (No3)2 would be required to yield 25g of pbcl on the addition of excess of Nacl solution (Pb=207,N=14,O=16,Na=23,Cl=35.5)
If your equation is
Pb(NO3)2 + 2NaCl → PbCl + 2NaNO3
then each mole of Pb(NO3)2 yields one mole of PbCl.
So, how many moles of PbCl do you have in 25 grams?
convert that to grams of Pb(NO3)2
You need to start over. Lead(II) chloride is PbCl2. Enough said?
And lead (II) trioxonitrate(V) is not an IUPAC approved name for lead(II) nitrate

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