Asked by Daniel
what mass of lead || trioxonitrate(v) would be required to yield 12g of lead || chloride on the addition of excess sodium chloride solution (pb=207,N=1,o=16,Na=23,cl=35.5) pb(No)+2Nacl pbcl+2NaNo
Answers
Answered by
DrBob222
That chemical with the funny name is properly called lead(II) nitrate.
Pb(NO3)2 + 2NaCl ==> PbCl2 + 2NaNO3.
mols PbCl2 needed = grams/molar mass = ?
You get 1 mol PbCl2 for every 1 mol Pb(NO3)2 used initially.
Then grams Pb(NO3)2 = mols Pb(NO3)2 x molar mass Pb(NO3)2 = ?
Post your work if you get stuck.
Pb(NO3)2 + 2NaCl ==> PbCl2 + 2NaNO3.
mols PbCl2 needed = grams/molar mass = ?
You get 1 mol PbCl2 for every 1 mol Pb(NO3)2 used initially.
Then grams Pb(NO3)2 = mols Pb(NO3)2 x molar mass Pb(NO3)2 = ?
Post your work if you get stuck.
Answered by
Anonymous
did the solution
Answered by
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What is the mass
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