Question

an archer shoots an arrow straight up into the air with an initial velocity of 45 m/s (U). calculate the maximum height of the arrow
bobpursley
Conservation of energy applies.
Initial KE= final PE
1/2 m v^2=mgh (at the max height, velocity is zero)
h= v^2/g or 45^2/((2)(9.8)) that is pretty high.

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