Asked by Elisa
An archer shoots an arrow toward a 300 g target that is sliding in her direction at a speed of 2.35 m/s on a smooth, slippery surface. The 22.5 g arrow is shot with a speed of 41.0 m/s and passes through the target, which is stopped by the impact. What is the speed of the arrow after passing through the target?
Answers
Answered by
drwls
The target loses momentum in the opposite direction to the arrow's motion, by an amount 300 g*2.35 m/s = 705 g m/s.
The arrow loses momentum equal to that, in the direction of its motion. Divide 705 g m/s by 22.5 g to get the decrease in the arrow's velocity. Then subtract that from the inital velocity.
Or just solve this equation:
Arrow mass*Initial arrow speed
-Target mass * Initial target speed = Arrow mass*Final arrow speed
The arrow loses momentum equal to that, in the direction of its motion. Divide 705 g m/s by 22.5 g to get the decrease in the arrow's velocity. Then subtract that from the inital velocity.
Or just solve this equation:
Arrow mass*Initial arrow speed
-Target mass * Initial target speed = Arrow mass*Final arrow speed