Asked by Branco
How do you prove this identity?
cos2x*tan(π\4-x)= 1-sin2x
cos2x*tan(π\4-x)= 1-sin2x
Answers
Answered by
oobleck
tan(π/4 - x) = (tanπ/4 - tanx)/(1 + tanπ/4 tanx)
= (1-tanx)/(1+tanx)
= (cosx-sinx)/(cosx+sinx)
see what you can do with that.
= (1-tanx)/(1+tanx)
= (cosx-sinx)/(cosx+sinx)
see what you can do with that.
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