Asked by Zapper
Describe how you would estimate the square root of a number that is not a perfect square with out using a calculator.
IF anyone could help me to have an understanding of what this question wants or means I'd appreciate it. Thanks
IF anyone could help me to have an understanding of what this question wants or means I'd appreciate it. Thanks
Answers
Answered by
Damon
given a^2
guess x for sqrt a
a^2 = (x + y)^2
a^2 = x^2 + 2 x y + y^2
if my guess was perfect, y = 0
if just a little off, then y^2 is much less than 2 x y
so I approximate
2 x y = a^2 - x^2
for example if I want the square root of 10
a^2 = 10
guess x = 3 so x^2 = 9
2 (3) y = 10 - 9 = 1
y = 1/6
so my next guess at sqrt 10 is 3+1/6 or 3.167 = new x
well how far off is that?
3.167^2 = 10.03 , not bad. The next try using x = 3.167 will be about as close as your calulator could come:)
(my calculator says sqrt 10 = 3.16227766 )
guess x for sqrt a
a^2 = (x + y)^2
a^2 = x^2 + 2 x y + y^2
if my guess was perfect, y = 0
if just a little off, then y^2 is much less than 2 x y
so I approximate
2 x y = a^2 - x^2
for example if I want the square root of 10
a^2 = 10
guess x = 3 so x^2 = 9
2 (3) y = 10 - 9 = 1
y = 1/6
so my next guess at sqrt 10 is 3+1/6 or 3.167 = new x
well how far off is that?
3.167^2 = 10.03 , not bad. The next try using x = 3.167 will be about as close as your calulator could come:)
(my calculator says sqrt 10 = 3.16227766 )
Answered by
Zapper
Thanks I understand it much better now.
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