Question
the profit of a company, in dollars, is the difference between the company's revenue and cost. the cost C(x), and R(x) are functions for a particular company. the x represents the number of items produced and sold to distributors. C(x)=2000+60x R(x)=860x-x^2
Determine the maximum profit of the coming.
Determine the maximum profit of the coming.
Answers
p = R - C = -x^2 + 800 x - 2000
dp/dx = -2x + 800 = 0 at max or min
so x = 400 at max or min of p
is it a max or a min
well if x is large - or +, the sides of the parabola zoom negative so the vertex was a max (if you do not know calculus complete the square to find vertex of that parabola)
then
p = -160,000 + 800(400) - 2000
= -160, 000 + 320,000 - 2,000
dp/dx = -2x + 800 = 0 at max or min
so x = 400 at max or min of p
is it a max or a min
well if x is large - or +, the sides of the parabola zoom negative so the vertex was a max (if you do not know calculus complete the square to find vertex of that parabola)
then
p = -160,000 + 800(400) - 2000
= -160, 000 + 320,000 - 2,000
how do you find dp/dx?
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