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Determine the required nominal diameter of a threaded steel rod to carry an axial load of 16,000 pounds in tension if the tensile stress of 20,000 psi is permitted.


16 years ago

Answers

bobpursley
Find the area...

Area*20kpsi=16kpouds
area= 800 in^2
PI*(Diameter/2)^2=800
solve for diameter in inches.
16 years ago
David
Thanks bob mind helping me with one more? The questions all ready posted, same subject.
16 years ago

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