Asked by David
Determine the required nominal diameter of a threaded steel rod to carry an axial load of 16,000 pounds in tension if the tensile stress of 20,000 psi is permitted.
Answers
Answered by
bobpursley
Find the area...
Area*20kpsi=16kpouds
area= 800 in^2
PI*(Diameter/2)^2=800
solve for diameter in inches.
Area*20kpsi=16kpouds
area= 800 in^2
PI*(Diameter/2)^2=800
solve for diameter in inches.
Answered by
David
Thanks bob mind helping me with one more? The questions all ready posted, same subject.
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