Asked by nini
△ABC has vertices A(−6,5), B(−2,5), and C(−6,0).
What is the area of △ABC?
20 units2
9 units2
14 units2
10 units2
im not sure what it is can someone help????
What is the area of △ABC?
20 units2
9 units2
14 units2
10 units2
im not sure what it is can someone help????
Answers
Answered by
Ms Pi 3.14159265358979323
sketch it out : )
Then it is base length x height and then divided by 2
Once you have the picture you can find the measurements.
Then it is base length x height and then divided by 2
Once you have the picture you can find the measurements.
Answered by
Ms Pi 3.14159265358979323
The base length is from -6 to -2, which is 4 units...
The height is from (-6,0) up to (-6,5)
Hope this helps : )
The height is from (-6,0) up to (-6,5)
Hope this helps : )
Answered by
henry2,
(AB)^2 = (-2+6)^2 + (5-5)^2 = 16.
AB = 4.
(BC)^2 = (-6+2)^2 + (0-5)^2 = 41,
BC = sqrt41. = 6.4.
(AC)^2 = (-6+6)^2 + (0-5)^2 = 25,
AC = 5.
(5/2)^2 + h^2 = 6.4^2,
h = 5.89.
A = hb/2 = 5.89*5/2 = 14.7.
AB = 4.
(BC)^2 = (-6+2)^2 + (0-5)^2 = 41,
BC = sqrt41. = 6.4.
(AC)^2 = (-6+6)^2 + (0-5)^2 = 25,
AC = 5.
(5/2)^2 + h^2 = 6.4^2,
h = 5.89.
A = hb/2 = 5.89*5/2 = 14.7.
Answered by
hi
so what is the answer?
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