Question
What are the vertices of the hyperbola x^2/9 - y^2/4=1
I'm not sure of how to start or what equation to use.
Show steps please.
I'm not sure of how to start or what equation to use.
Show steps please.
Answers
Steve
just set y=0. x = ±3
So, the vertices are at (±3,0)
You know that it has to be y=0, because if x=0, -y^2/4 = 1, meaning y^2 has to be negative.
So, the vertices are at (±3,0)
You know that it has to be y=0, because if x=0, -y^2/4 = 1, meaning y^2 has to be negative.
Julissa
Thank you so much...