Asked by Nela
Jake is 15 years older than liz while naida is 19 years younger than liz. Find their present ages if age in 4 years is 5 more than the sum of naida's age 7 years from now and liz's age 11 years ago
Answers
Answered by
Reiny
Liz's present age --- x
Jake's present age --- x+15
Naida's present age --- x-19
Guessing that your typo is: Find their present ages if Jake's age in ....
Jake's age 4 years from now: x+15 + 4 = x + 19
naida's age 7 years from now = x-19 + 7 = x - 12
liz's age 11 years ago = x-11
Find their present ages if Jake's age in 4 years is 5 more than the sum of naida's age 7 years from now and liz's age 11 years ago
---> x+19 = (x-12) + (x-11) + 5
x+19 = 2x - 18
x = 37
State their present ages by going back to my definitions
Verify my answer after checking my arithmetic
Jake's present age --- x+15
Naida's present age --- x-19
Guessing that your typo is: Find their present ages if Jake's age in ....
Jake's age 4 years from now: x+15 + 4 = x + 19
naida's age 7 years from now = x-19 + 7 = x - 12
liz's age 11 years ago = x-11
Find their present ages if Jake's age in 4 years is 5 more than the sum of naida's age 7 years from now and liz's age 11 years ago
---> x+19 = (x-12) + (x-11) + 5
x+19 = 2x - 18
x = 37
State their present ages by going back to my definitions
Verify my answer after checking my arithmetic