Question

Point R(3,7) and point S(−1,−4) are located within the coordinate plane.

What is the distance between the two points?

137
194−−−√
13−−√
137−−−√
could someone help me understand please

Answer 1

X = -1-3 = -4.
Y = -4 -7 = -11.
d^2 = X^2+Y^2 = (-4)^2 + (-11)^2 = 137.
d =

Answer 2

the points are 4-units apart in the x-direction
... and 11-units apart in the y-direction

the axes are at right angles to each other
... so you can use Pythagoras to find the distance

(total distance)^2 = (x-distance)^2 + (y-distance)^2

d^2 = 4^2 + 11^2 = 16 + 121

Answer 3

its 137−−−√ I just finished the exam.