Asked by Anonymous
The common adult mole (Scalopus aquaticus)
weighs about 75 grams. So, how much would
a mole of moles weigh?
1. 4.51 × 10−22 kg
2. 4.51 × 1025 kg
3. 1.25 × 1022 kg
4. 1.25 × 10−19 kg
5. 1.25 × 10−22 kg
6. 4.51 × 1022 kg
weighs about 75 grams. So, how much would
a mole of moles weigh?
1. 4.51 × 10−22 kg
2. 4.51 × 1025 kg
3. 1.25 × 1022 kg
4. 1.25 × 10−19 kg
5. 1.25 × 10−22 kg
6. 4.51 × 1022 kg
Answers
Answered by
Damon
75 g = 0 .075 kg
6.022140857 * 10^23 * 0.075 kg = 6.022140857 * 10^22 * 0.75
= approximately (3/4)(6)*10^22 = 4.5 * 10^22 kg
6.022140857 * 10^23 * 0.075 kg = 6.022140857 * 10^22 * 0.75
= approximately (3/4)(6)*10^22 = 4.5 * 10^22 kg