F = G M m /r^2
if M' = 7 M
and r' = 6 r so r'^2 = 36 r^2
then
F' = G M' m /r'^2 = G (7M) m/ 36 r^2 = G M m/r^2 *[ 7/36]
on earth we say G M/r^2 = g
so new weight = g m (7/36) = 710 (7/36)
You weigh 710 N.
What would you weigh if the Earth were
seven times as massive as it is and its radius
were six times its present value?
Answer in units of N.
2 answers
gravity is an inverse-square relationship
... proportional to the product of the masses
... and inversely proportional to the square of the distance between centers
710 * 7 / 6^2
... proportional to the product of the masses
... and inversely proportional to the square of the distance between centers
710 * 7 / 6^2
1 answer