Asked by Nidia

can anyone help me with this problem?

6x-5y+20=0
Answered by Damon
Graph it.
it is a straight line that goes through (0,4) and (-10/3,0)
Answered by Amy
how did you figure that out?
Answered by Damon
let x = 0
then -5 y = -20
y = 4 so (0,4) is on the line
then
let y = 0
6 x = -20
x = -20/6 = -10/3
so (-10/3,0) is on the line
Answered by Nidia
yeah how did you figure that out? lol i really do need help.
Answered by Nidia
ha jk never mind what i said
Answered by Amy
hey so how can you explain this?

x+3=0
Answered by Damon
That is x = -3 for any y at all.
Therefore its graph is a vertical line through x = -3
Answered by Nidia
what if y is not shown, like in this equation?
2x-=0

what do you set y as? i don't get it.
Answered by Damon
If 2 x = 0, y can be anything just like Amy's question.
x = 0
That is a vertical line through the origin, the y axis in fact.
Answered by Nidia
sorry i typed the question wrong the equation is :

2x-7=0
Answered by Damon
By the way if you had
y = 0
then x could be anything.
That would be a horizontal line through the origin, namely the x axis.
or say
y = 3
That would be a horizontal line through (0,3)
Answered by Damon
2x-7=0
2x = 7
x = 7/2, y can be anything
vertical line through (3.5 , 0)
It could be (3.5,0)
or
(3.5 , -57312537.3) or any other y
Answered by Amy
what if x is on the right side of the equation like

2y+5= -2x
Answered by Damon
Do it exactly the same way
x = 0, then y = -5/2 so (0,-5/2)
y = 0 then x = -5/2 so (-5/2, 0)
Answered by Jessica
thanks!!!!!!!!!!!!
Answered by Amy
yeah what she said thanx!!!!!!!!
Answered by Damon
You are welcome :)