Asked by Anna
A plane takes 1.2 h to fly to a point that is 420 km directly west of its original position if the wind was blowing at a velocity of 65km/h [E 25degree N] what was the velocity of the plane relative to the wind?
Answers
Answered by
oobleck
plane: p = 420km/1.2hr = 350 @ W
wind: w = 65 @ E25N
p relative to w is just p-w so subtract the vectors in the usual way.
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wind: w = 65 @ E25N
p relative to w is just p-w so subtract the vectors in the usual way.
.
Answered by
henry2,
Vp + Vw = 420/1.2 = 350km/h[180o].
Vp + 65[25o] = 350[18o],
Vp = 350[180] - 65[25o],
Vp = (350*cos180-65*cos25) + (350*sin180-65*sin25)I,
Vp = -409 - 27.5i = 410km/h[3.85o] S. of W.
Vp + 65[25o] = 350[18o],
Vp = 350[180] - 65[25o],
Vp = (350*cos180-65*cos25) + (350*sin180-65*sin25)I,
Vp = -409 - 27.5i = 410km/h[3.85o] S. of W.
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