h/d = tan 27°
so find d when h=875
if flight distance is f,
d/f = cos 27°
the time needed is thus f/651 hours
tanθ = 875/400
an air plane takes off with an elevation of 27degrees. what is the total land distance the plane reaches a cruising altitude of 875 feet ? if the plane is traveling at a steady speed of 651 feet per hour, how much time will it take the plane to reach its cruising distance? what would be the angle of elevation if the plane starts descending when it is 400 feet away from the air port landing stri?
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This is just too SIMPLE!!1
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