Asked by ariana
solve the absolute value equation
3{2x-2} + 8 = 20
Help (with baby steps please)
I know answer is x=-1 or x=3
( I get the 3 but not the -1)
thank you again
3{2x-2} + 8 = 20
Help (with baby steps please)
I know answer is x=-1 or x=3
( I get the 3 but not the -1)
thank you again
Answers
Answered by
Amy
Distribute the 3:
6x - 6 + 8 = 20
Subtract 8-6:
6x + 2 = 20
Subtract 2:
6x = 20 -2
6x = 18
Divide 6 on both sides:
(6x/6) = 18/6
x = 3
(x = -1 is not an answer)
6x - 6 + 8 = 20
Subtract 8-6:
6x + 2 = 20
Subtract 2:
6x = 20 -2
6x = 18
Divide 6 on both sides:
(6x/6) = 18/6
x = 3
(x = -1 is not an answer)
Answered by
Reiny
3|2x-2| + 8 = 20
3|2x-2| = 12
|2x-2| = 4
2x - 2 = 4 OR 2x-2 = -4
2x = 6 OR 2x = -2
x = 3 OR x = -1
both answers are valid
3|2x-2| = 12
|2x-2| = 4
2x - 2 = 4 OR 2x-2 = -4
2x = 6 OR 2x = -2
x = 3 OR x = -1
both answers are valid
Answered by
oobleck
3|2x-2| + 8 = 20
3|2x-2| = 12
|2x-2| = 4
|x-1| = 2
x-1 = ±2
x = 1±2
x = 3 or -1
3|2x-2| = 12
|2x-2| = 4
|x-1| = 2
x-1 = ±2
x = 1±2
x = 3 or -1
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