Asked by Anonymous
Terry and Phyllis went to the park to train for a long distance run. Terry reached earlier and started her run 10 minutes befor Phyllis arrived and joined in. Terry finished 5 minutes beforw Phyllis. They both ran the same distance. At the point when Terry finished, Phyllis had completed 5/6 of the joirney and still had 1 mile to go. Find each of their speeds. Who was faster? Give the answers in miles per hour.
Answers
Answered by
Damon
step one:
5/6 left one mile to go
so
one mile is 1/6 of the course
so
It is 6 miles long
-----------------------------------------------------
now times
say Terry started at noon and finished at t minutes after so ran t min
P started at 10 past and finished at t + 5 so ran t -5 min
at t, P had run 5 miles and T had run 6 miles
if ST is speed of T
so 6 miles = ST * t where ST is speed of T
5 miles = SP * (t-10)
6 miles = SP * (t-5)
=======
three equations, three unknowns
5 = SP t - 10 SP
6 = SP t -5 SP
------------------- subtract
-1 = -5 SP
so speed of P = 1/5 mile/min (times 60 = 12 miles/hour)
go back and get t and ST
5/6 left one mile to go
so
one mile is 1/6 of the course
so
It is 6 miles long
-----------------------------------------------------
now times
say Terry started at noon and finished at t minutes after so ran t min
P started at 10 past and finished at t + 5 so ran t -5 min
at t, P had run 5 miles and T had run 6 miles
if ST is speed of T
so 6 miles = ST * t where ST is speed of T
5 miles = SP * (t-10)
6 miles = SP * (t-5)
=======
three equations, three unknowns
5 = SP t - 10 SP
6 = SP t -5 SP
------------------- subtract
-1 = -5 SP
so speed of P = 1/5 mile/min (times 60 = 12 miles/hour)
go back and get t and ST
Answered by
Damon
Grade 6 ????
Answered by
Anonymous
Yes it’s grade 6
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