Question
How do you find the definite integral of an absolute function?
∫_0^3|2x-3|
lower limit= 0
upper limit = 3
∫_0^3|2x-3|
lower limit= 0
upper limit = 3
Answers
drwls
Integrate it in two pieces.
For x<1.5, |2x -3| = -2x + 3
For x>or=1.5, |2x -3| = 2x + 3
I have no idea why you have the cube of zero in front of the |2x -3| What is the _0^3 supposed to be?
For x<1.5, |2x -3| = -2x + 3
For x>or=1.5, |2x -3| = 2x + 3
I have no idea why you have the cube of zero in front of the |2x -3| What is the _0^3 supposed to be?
Stephen
i don't know either lol, i tried to get it from word document and i copied and pasted it that way
Stephen
"For x<1.5, |2x -3| = -2x + 3"
don't you mean .2x - 3?
don't you mean .2x - 3?
drwls
No. Think about it. If x<1.5, 2x -3 is negative. The absolute value process reverses the signs of what is inside.