Asked by Stephen
How do you find the definite integral of an absolute function?
∫_0^3|2x-3|
lower limit= 0
upper limit = 3
∫_0^3|2x-3|
lower limit= 0
upper limit = 3
Answers
Answered by
drwls
Integrate it in two pieces.
For x<1.5, |2x -3| = -2x + 3
For x>or=1.5, |2x -3| = 2x + 3
I have no idea why you have the cube of zero in front of the |2x -3| What is the _0^3 supposed to be?
For x<1.5, |2x -3| = -2x + 3
For x>or=1.5, |2x -3| = 2x + 3
I have no idea why you have the cube of zero in front of the |2x -3| What is the _0^3 supposed to be?
Answered by
Stephen
i don't know either lol, i tried to get it from word document and i copied and pasted it that way
Answered by
Stephen
"For x<1.5, |2x -3| = -2x + 3"
don't you mean .2x - 3?
don't you mean .2x - 3?
Answered by
drwls
No. Think about it. If x<1.5, 2x -3 is negative. The absolute value process reverses the signs of what is inside.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.