Asked by Hannah
Find the definite integral that represents the arc length of the curve y=sqrt(x) over the interval [0, 3]
Answers
Answered by
Anonymous
S=definite integral(a÷b)sqroot[1+(dy/dx)^2]
dy/dx=1/2sqroot(x)
(dy/dx)^2=1/4x
S=definite integral(0÷3)sqroot(1+1/4x)
If you don't know how to solve that integral in google type:
wolfram alpha
When you see list of results click on:
Wolfram Alpha:Computation Knowweledge Engine
When page be open in rectangle type:
sqroot(1+1/4x)
and click =
After few seconds you will see everything about that expresion.
In rectangle Indefinite integral:
click option Show steps
dy/dx=1/2sqroot(x)
(dy/dx)^2=1/4x
S=definite integral(0÷3)sqroot(1+1/4x)
If you don't know how to solve that integral in google type:
wolfram alpha
When you see list of results click on:
Wolfram Alpha:Computation Knowweledge Engine
When page be open in rectangle type:
sqroot(1+1/4x)
and click =
After few seconds you will see everything about that expresion.
In rectangle Indefinite integral:
click option Show steps
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.