Asked by I'm Just a Girl
1. The value of y varies directly with x. If x=3, then y = 21. What is the value of x when y = 105? A. 3/5 B.3 C. 7 D. 15
Pls help I been working on this for forever now.
Pls help I been working on this for forever now.
Answers
Answered by
Reiny
"The value of y varies directly with x" ----> y = kx
when x=3, y=21
21 = k(3)
k = 7
so we have y = 7x
plug in y= 105 and solve for x
when x=3, y=21
21 = k(3)
k = 7
so we have y = 7x
plug in y= 105 and solve for x
Answered by
I'm Just a Girl
Um......I guess my answer for this equation or problem would be D. 15. Pls let me know if I am wrong.
Answered by
Reiny
15 is the correct answer.
Why are you confused. What I did is the standard way of handling direct variations.
You could set up a ratio .....
y1/y2 = x1/x2
in your case x1=3 and y1 =21
find x2 when x2 = 105
21/105 = 3/x2
cross-multiply
21x2 = 315
x2 = 315/21 = 15
Why are you confused. What I did is the standard way of handling direct variations.
You could set up a ratio .....
y1/y2 = x1/x2
in your case x1=3 and y1 =21
find x2 when x2 = 105
21/105 = 3/x2
cross-multiply
21x2 = 315
x2 = 315/21 = 15
Answered by
I'm Just a Girl
Reiny thanks so much. But I need help with one more thing.
Answered by
I'm Just a Girl
9. What is the equation in slope-intercept form of the line that passes through the point (5,0) and is parallel to the line represented by y=1.2x+3.8? And just for a note The slopes of a parallel line are the same. A. y=1.3x-6 B. y=-1.2x+6 C. y=1.2x+5 D. y = 1.2x-5
My answer is um....B
My answer is um....B
Answered by
oobleck
y=1.2x+3.8 has slope 1.2
Now use the point-slope form for your desired line:
y-5 = 1/2 (x-0)
So, not B.
Now use the point-slope form for your desired line:
y-5 = 1/2 (x-0)
So, not B.
Answered by
Josiah
so what is the slope then?
Answered by
Hi
the answer is D. 15
Answered by
Delilah
It would be D 15 because it is a proportion so it would be
3/21=x/105
3/21=x/105
Answered by
Ethan
For a line equation for the form of y = mx + b, the slope is m,
m in this equation (y = 1.2x + 3.8) is 1.2,
It is not equation A since it has a slope of 1.3,
It is not equation B since it has a slope of -1.2 which makes it cross over line y = 1.2x + 3.8. (perpendicular)
m in this equation (y = 1.2x + 3.8) is 1.2,
It is not equation A since it has a slope of 1.3,
It is not equation B since it has a slope of -1.2 which makes it cross over line y = 1.2x + 3.8. (perpendicular)
Answered by
Ethan
It would not be D even though it has a slope of 1.2. (for other answers with the same slope don't assume it is correct without proof!) The y values don't match up. (find some points on the line and compare them with the equation y = 1.2x + 3.8; look at the bottom for how to find points on a line.)
C is the answer. Take the equations y = 1.2x + 5 and y = 1.2x + 3.8 and make tables with them. As you can see the y values line up.
Equation C (y = 1.2x + 5) Equatioion y = 1.2x + 3.8
x y x y
-1 2.6 -2 2.6
0 3.8 -1 3.8
1 5 0 5
2 6.2 1 6.2
3 7.4 2 7.4
Finding Points on a Line
To find points on the line y = mx + b,
Choose x and solve the equation for y,
Example,
Find two points on the line y = 1.2x + 3.8:
Let x =1. Substitute x = 1 into y = 21.x + 3.8 and solve for y,
y = 1.2(1) + 3.8 = 1.2 + 3.8 = 5
(1,5)
C is the answer. Take the equations y = 1.2x + 5 and y = 1.2x + 3.8 and make tables with them. As you can see the y values line up.
Equation C (y = 1.2x + 5) Equatioion y = 1.2x + 3.8
x y x y
-1 2.6 -2 2.6
0 3.8 -1 3.8
1 5 0 5
2 6.2 1 6.2
3 7.4 2 7.4
Finding Points on a Line
To find points on the line y = mx + b,
Choose x and solve the equation for y,
Example,
Find two points on the line y = 1.2x + 3.8:
Let x =1. Substitute x = 1 into y = 21.x + 3.8 and solve for y,
y = 1.2(1) + 3.8 = 1.2 + 3.8 = 5
(1,5)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.