Asked by Word
Having studied the data for patterns and trends, you should now be able to draw some conclusions about knowing the half-life of the element Lokium would help you determine the absolute age of rock in which this element is found. imagine you have found a rock that has 5 grams (a.k.a. cubes) of Lokium and 95 grams of DOL. Determine the absolute age of that rock. Assume that each trail in your experiment represents 1,000 years. Show all work.
Answers
Answered by
Damon
I guess you have a rock weighing 100 grams
I guess it started out all Lokium at t = 0 ?
if it has a half life of T years
then
fraction Lokium = (1/2)^n where n is the number of half lives
here
fraction of Lolium seems to be 5/100
so
5/100 = (1/2)^n
log .05 = n log .5
n = log .05/log .5 = -1.3/ -0.301 = 4.33 half lives
so that rock is 4.33 half lives old
Now I guess you have experimental data that gives you fraction of Lokium versus time
something like'
fraction mass/original mass = f = e^-kt
find k from the data using ln f = - k t
then for half life we want to solve for T when the fraction is 1/2
1/2 = e^-kT
ln 0.5 = - k T
T = 0.693 / k where T is the half life
I guess it started out all Lokium at t = 0 ?
if it has a half life of T years
then
fraction Lokium = (1/2)^n where n is the number of half lives
here
fraction of Lolium seems to be 5/100
so
5/100 = (1/2)^n
log .05 = n log .5
n = log .05/log .5 = -1.3/ -0.301 = 4.33 half lives
so that rock is 4.33 half lives old
Now I guess you have experimental data that gives you fraction of Lokium versus time
something like'
fraction mass/original mass = f = e^-kt
find k from the data using ln f = - k t
then for half life we want to solve for T when the fraction is 1/2
1/2 = e^-kT
ln 0.5 = - k T
T = 0.693 / k where T is the half life
Answered by
Samuel
could you do the fraction Lolium be 40/100
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