Asked by Zuhayr
Water flows from the bottom of a storage tank at a rate of r(t) = 400 − 8t liters per minute, where 0 ≤ t ≤ 50. Find the amount of water that flows from the tank during the first 45 minutes.
Answers
Answered by
Ms Pi_3.14159265358979
From a gentle stand point...
There are only 400 L in the tank.
r(t) = 400 − 8t
If time is 45 minutes then
r(t) = 400 - 8(45)
= 400 - 360
= 40
So 360 Litres has left the tank : )
There are only 400 L in the tank.
r(t) = 400 − 8t
If time is 45 minutes then
r(t) = 400 - 8(45)
= 400 - 360
= 40
So 360 Litres has left the tank : )
Answered by
oobleck
r(t) = 400 − 8t
If v is the volume, r(t) = dv/dt. So,
v(t) = 400t - 4t^2
v(45) = 9900
If v is the volume, r(t) = dv/dt. So,
v(t) = 400t - 4t^2
v(45) = 9900
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