Asked by Ande
Find the Foci and directrices of the following parabola of the pattern:
y^2=8x at (2,4)
y^2=24x at (5/2, 6)
x^2=12y at (6, 3)
x^2=5y at (5,5)
y^2=8x at (2,4)
y^2=24x at (5/2, 6)
x^2=12y at (6, 3)
x^2=5y at (5,5)
Answers
Answered by
Reiny
Parabolas in the form y^2 = 4px have an axis of symmetry on the x-axis,
with a focus at(p,0) and a vertical directrix of x = -p
similarly,
Parabolas in the form x^2 = 4py have an axis of symmetry on the y-axis,
with a focus at (0,p) and a horizontal directrix of y = -p
so for y^2=24x , 4px = 24x and p = 6
so the focus is (6,0) and the directrix is x = -6
I don't know what the point (5/2, 6) has to do with it, it doesn't even lie on the parabola
do the others the same way
with a focus at(p,0) and a vertical directrix of x = -p
similarly,
Parabolas in the form x^2 = 4py have an axis of symmetry on the y-axis,
with a focus at (0,p) and a horizontal directrix of y = -p
so for y^2=24x , 4px = 24x and p = 6
so the focus is (6,0) and the directrix is x = -6
I don't know what the point (5/2, 6) has to do with it, it doesn't even lie on the parabola
do the others the same way
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