Asked by Anonymous
Needing a little help with this one:
The data in the table represents the average number of daylight hours each month in Springfield in 2015, rounded to the nearest quarter-hour.
January - 9.5
February - 10.5
March - 12
April - 13.25
May - 14.5
June - 15
July - 14.75
August - 13.75
September - 12.5
October - 11.0
November - 9.75
December - 9.25
Write an equation that best models the data.
What is the expected number of daylight hours in March 2020? Explain.
Please advise (and please show work so I know how to do this)!
The data in the table represents the average number of daylight hours each month in Springfield in 2015, rounded to the nearest quarter-hour.
January - 9.5
February - 10.5
March - 12
April - 13.25
May - 14.5
June - 15
July - 14.75
August - 13.75
September - 12.5
October - 11.0
November - 9.75
December - 9.25
Write an equation that best models the data.
What is the expected number of daylight hours in March 2020? Explain.
Please advise (and please show work so I know how to do this)!
Answers
Answered by
oobleck
the period is 12 (months)
sin(kx) has period 2π/k, so k = π/6
max is 15
min is 9.25
so, amplitude = (max-min)/2 = 2.875
center line is (max+min)/2 = 12.125
max occurs when x=6, so we can model with a cosine curve shifted right by 6
y = 12.125 + 2.875 cos(π/6 (x-6))
check:
https://www.wolframalpha.com/input/?i=12.125+%2B+2.875cos%28%CF%80%2F6+%28x-6%29%29+for+0+%3C%3D+x+%3C%3D+12
sin(kx) has period 2π/k, so k = π/6
max is 15
min is 9.25
so, amplitude = (max-min)/2 = 2.875
center line is (max+min)/2 = 12.125
max occurs when x=6, so we can model with a cosine curve shifted right by 6
y = 12.125 + 2.875 cos(π/6 (x-6))
check:
https://www.wolframalpha.com/input/?i=12.125+%2B+2.875cos%28%CF%80%2F6+%28x-6%29%29+for+0+%3C%3D+x+%3C%3D+12
Answered by
Damon
well the period seems to be 12 months :) It better repeat the next year more or less. so make it a sine wave with period of 12 moths december = 0 and next december = one period = 12 months
in other words redraw starting at month = 0
0 -- December last year = 9.25
1 --- January - 9.5
2 ----February - 10.5
March - 12
April - 13.25
May - 14.5
June - 15
July - 14.75
August - 13.75
September - 12.5
October - 11.0
November - 9.75
12 ---- December - 9.25
so it will be 9.25 + sin (2 pi t/T) where t is the time after december in months and T is 12
in other words redraw starting at month = 0
0 -- December last year = 9.25
1 --- January - 9.5
2 ----February - 10.5
March - 12
April - 13.25
May - 14.5
June - 15
July - 14.75
August - 13.75
September - 12.5
October - 11.0
November - 9.75
12 ---- December - 9.25
so it will be 9.25 + sin (2 pi t/T) where t is the time after december in months and T is 12
Answered by
Damon
ignore what I did --- I left amplitude out and should be cosine about june use oobleck solution.
Answered by
anke
thanks you guys! oobleck is right
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.