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It is observed that rider A closes the 48 gap in a time of 6 seconds (a=ft/s^2). a) What speed was rider A moving while located 48 feet behind rider B? b) As timed from when rider A was 48 feet behind rider B, how many seconds elapse before rider A matches rider B's speed? (rider B has a constant speed of 54ft/s.)
5 years ago

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