Ask a New Question

Asked by Brooklyn

A BMX rider is coming up to a ramp that is set to 23.0° and the end point is 1.60 m above the ground. They travel up the ramp at a steady speed of 9.20 m/s. What speed will they have just before they hit the ground?
9 years ago

Answers

Answered by Steve
Starting at the top of the ramp, the rider's height is

h(t) = 1.60 sin23° t - 4.9t^2

So, find t when h=0

The rider's velocity when he hits the ground is

Vx = 1.60 cos23°
Vy = 1.60 sin23° - 9.8t
So, the speed v at time t is found using
v^2 = Vx^2 + Vy^2
9 years ago

Related Questions

An elevator and rider have a mass of 1600 kg combined. What is the tension force in the cable lift... The weight of the rider is one force and gravity is another. Do I need a comma in this sentence?... The height of the rider on a Ferris Wheel can be modeled by a cosine function. At time t = 0, a ride... It is observed that rider A closes the 48 gap in a time of 6 seconds (a=ft/s^2). a) What speed was r... a bicycle and a rider together have a mass of 90kg. if the bicycle moves at 6.0 m/s, how much force... In "Rider in the City," what type of character is Rider? a protagonist, because he is the main ch... In "Rider in the City," what type of character is Margie? static character because she changes d... "That rider of yours said he's not debted to him and he can come and go as he pleases. That right?"... Blank is when a rider looks back on something that happened and then draws a personal conclusion
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use