A grandfather clock has a pendulum that consists of a thin brass disk of radius r = 17.61 cm and mass 1.177 kg that is attached to a long thin rod of negligible mass. The pendulum swings freely about an axis perpendicular to the rod and through the end of the rod opposite the disk, as shown in the figure. If the pendulum is to have a period of 1.752 s for small oscillations at a place where g = 9.828 m/s2, what must be the rod length L?
I think my error is in Inertia i only calculated for the disk because rod mass is negligible, but not 100% sure if anyone can do it would be great help. Thank you (;
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Does the rod attach to the center of the disk or to the outer radius? After computing the moment of inertia around the disk center you must add to that m*x^2 where x is either L or L+0.1761
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