Asked by Gavin
What is the speed of a rock if you drop it from a tall bridge
Answers
Answered by
Damon
v = g t
at distance d below bridge:
d = (1/2) g t^2
so
t = sqrt (2 d/g)
and
v = g sqrt (2 d/g) = sqrt (2 g d)
at distance d below bridge:
d = (1/2) g t^2
so
t = sqrt (2 d/g)
and
v = g sqrt (2 d/g) = sqrt (2 g d)
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